If someone tries to create an account on my site with the standard quick registration they are getting hit with this ugly error......
TABLE '(my db).JOS_SOCIAL_PRIVACY' DOESN'T EXIST SQL=INSERT INTO `CA1_SOCIAL_PRIVACY_ITEMS` (`PRIVACY_ID`, `USER_ID`, `UID`, `TYPE`, `VALUE`) SELECT `D`.`ID` AS `PRIVACY_ID`, '3689' AS `USER_ID`, `A`.`ID` AS `UID`, `D`.`TYPE`, `D`.`VALUE` FROM `CA1_SOCIAL_FIELDS` AS `A` LEFT JOIN `CA1_SOCIAL_FIELDS_STEPS` AS `B` ON `B`.`ID` = `A`.`STEP_ID` LEFT JOIN `CA1_SOCIAL_APPS` AS `C` ON `C`.`ID` = `A`.`APP_ID` LEFT JOIN (SELECT PI.`ID`, PI.TYPE, PI.RULE, IFNULL(PIM.`VALUE`, PI.VALUE) AS `VALUE` FROM JOS_SOCIAL_PRIVACY AS PI LEFT JOIN JOS_SOCIAL_PRIVACY_MAP AS PIM ON PI.`ID` = PIM.`PRIVACY_ID` AND PIM.`UTYPE` = 'PROFILES' AND PIM.`UID` = '1' WHERE PI.`TYPE` = 'FIELD') AS `D` ON `D`.`RULE` = `C`.`ELEMENT` WHERE `D`.`TYPE` = 'FIELD' AND `B`.`TYPE` = 'PROFILES' AND `B`.`UID` = '1' AND `A`.`ID` NOT IN (SELECT `E`.`UID` FROM `CA1_SOCIAL_PRIVACY_ITEMS` AS `E` WHERE `E`.`TYPE` = 'FIELD' AND `E`.`USER_ID` = '3689')
Any ideas on the cause / fix for this!
TABLE '(my db).JOS_SOCIAL_PRIVACY' DOESN'T EXIST SQL=INSERT INTO `CA1_SOCIAL_PRIVACY_ITEMS` (`PRIVACY_ID`, `USER_ID`, `UID`, `TYPE`, `VALUE`) SELECT `D`.`ID` AS `PRIVACY_ID`, '3689' AS `USER_ID`, `A`.`ID` AS `UID`, `D`.`TYPE`, `D`.`VALUE` FROM `CA1_SOCIAL_FIELDS` AS `A` LEFT JOIN `CA1_SOCIAL_FIELDS_STEPS` AS `B` ON `B`.`ID` = `A`.`STEP_ID` LEFT JOIN `CA1_SOCIAL_APPS` AS `C` ON `C`.`ID` = `A`.`APP_ID` LEFT JOIN (SELECT PI.`ID`, PI.TYPE, PI.RULE, IFNULL(PIM.`VALUE`, PI.VALUE) AS `VALUE` FROM JOS_SOCIAL_PRIVACY AS PI LEFT JOIN JOS_SOCIAL_PRIVACY_MAP AS PIM ON PI.`ID` = PIM.`PRIVACY_ID` AND PIM.`UTYPE` = 'PROFILES' AND PIM.`UID` = '1' WHERE PI.`TYPE` = 'FIELD') AS `D` ON `D`.`RULE` = `C`.`ELEMENT` WHERE `D`.`TYPE` = 'FIELD' AND `B`.`TYPE` = 'PROFILES' AND `B`.`UID` = '1' AND `A`.`ID` NOT IN (SELECT `E`.`UID` FROM `CA1_SOCIAL_PRIVACY_ITEMS` AS `E` WHERE `E`.`TYPE` = 'FIELD' AND `E`.`USER_ID` = '3689')
Any ideas on the cause / fix for this!